1122001122113 has 2 divisors, whose sum is σ = 1122001122114. Its totient is φ = 1122001122112.

The previous prime is 1122001122091. The next prime is 1122001122131. The reversal of 1122001122113 is 3112211002211.

It is a happy number.

Together with next prime (1122001122131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 916092094129 + 205909027984 = 957127^2 + 453772^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122001122113 - 2⁶ = 1122001122049 is a prime.

It is a super-2 number, since 2×1122001122113² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1122001122091 and 1122001122100.

It is not a weakly prime, because it can be changed into another prime (1122001122163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561000561056 + 561000561057.

It is an arithmetic number, because the mean of its divisors is an integer number (561000561057).

Almost surely, 2^{1122001122113} is an apocalyptic number.

It is an amenable number.

1122001122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122001122113 is an equidigital number, since it uses as much as digits as its factorization.

1122001122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1122001122113 its reverse (3112211002211), we get a palindrome (4234212124324).

The spelling of 1122001122113 in words is "one trillion, one hundred twenty-two billion, one million, one hundred twenty-two thousand, one hundred thirteen".