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11220022021423 is a prime number
BaseRepresentation
bin1010001101000101110101…
…1011010100110100101111
31110201121211121220102202211
42203101131123110310233
52432312101114141143
635510223523031251
72235422414412535
oct243213533246457
943647747812684
1011220022021423
113636425a20156
12131262280b527
1363507485b387
142ab0a2832155
15146cd279949d
hexa345d6d4d2f

11220022021423 has 2 divisors, whose sum is σ = 11220022021424. Its totient is φ = 11220022021422.

The previous prime is 11220022021399. The next prime is 11220022021517. The reversal of 11220022021423 is 32412022002211.

It is a weak prime.

It is an emirp because it is prime and its reverse (32412022002211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11220022021423 - 217 = 11220021890351 is a prime.

It is a super-2 number, since 2×112200220214232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11220022021394 and 11220022021403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11220022021723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610011010711 + 5610011010712.

It is an arithmetic number, because the mean of its divisors is an integer number (5610011010712).

Almost surely, 211220022021423 is an apocalyptic number.

11220022021423 is a deficient number, since it is larger than the sum of its proper divisors (1).

11220022021423 is an equidigital number, since it uses as much as digits as its factorization.

11220022021423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 11220022021423 its reverse (32412022002211), we get a palindrome (43632044023634).

The spelling of 11220022021423 in words is "eleven trillion, two hundred twenty billion, twenty-two million, twenty-one thousand, four hundred twenty-three".