Base | Representation |
---|---|
bin | 1010001101000110001010… |
… | …1111001000110010011011 |
3 | 1110201122001211112011002111 |
4 | 2203101202233020302123 |
5 | 2432312241420213313 |
6 | 35510240424213151 |
7 | 2235424545523153 |
oct | 243214257106233 |
9 | 43648054464074 |
10 | 11220111101083 |
11 | 3636471233005 |
12 | 131264860a1b7 |
13 | 63508a14a431 |
14 | 2ab0b05bd763 |
15 | 146cda4e343d |
hex | a3462bc8c9b |
11220111101083 has 2 divisors, whose sum is σ = 11220111101084. Its totient is φ = 11220111101082.
The previous prime is 11220111101077. The next prime is 11220111101107. The reversal of 11220111101083 is 38010111102211.
It is a weak prime.
It is an emirp because it is prime and its reverse (38010111102211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11220111101083 - 213 = 11220111092891 is a prime.
It is not a weakly prime, because it can be changed into another prime (11220111101063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610055550541 + 5610055550542.
It is an arithmetic number, because the mean of its divisors is an integer number (5610055550542).
Almost surely, 211220111101083 is an apocalyptic number.
11220111101083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220111101083 is an equidigital number, since it uses as much as digits as its factorization.
11220111101083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 22.
Adding to 11220111101083 its reverse (38010111102211), we get a palindrome (49230222203294).
The spelling of 11220111101083 in words is "eleven trillion, two hundred twenty billion, one hundred eleven million, one hundred one thousand, eighty-three".
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