Base | Representation |
---|---|
bin | 11001100000101111100001… |
… | …010001000100000100100011 |
3 | 112201021022221020112201010222 |
4 | 121200233201101010010203 |
5 | 104201301034231121011 |
6 | 1034344305125513255 |
7 | 32430161403132251 |
oct | 3140574121040443 |
9 | 481238836481128 |
10 | 112201210020131 |
11 | 328292a1a82211 |
12 | 1070141a27282b |
13 | 4a7b6b4746c2b |
14 | 1d9c7d348d5d1 |
15 | ce8926ecdddb |
hex | 660be1444123 |
112201210020131 has 2 divisors, whose sum is σ = 112201210020132. Its totient is φ = 112201210020130.
The previous prime is 112201210020019. The next prime is 112201210020143. The reversal of 112201210020131 is 131020012102211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112201210020131 is a prime.
It is a super-2 number, since 2×1122012100201312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112201210020331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56100605010065 + 56100605010066.
It is an arithmetic number, because the mean of its divisors is an integer number (56100605010066).
Almost surely, 2112201210020131 is an apocalyptic number.
112201210020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
112201210020131 is an equidigital number, since it uses as much as digits as its factorization.
112201210020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 112201210020131 its reverse (131020012102211), we get a palindrome (243221222122342).
The spelling of 112201210020131 in words is "one hundred twelve trillion, two hundred one billion, two hundred ten million, twenty thousand, one hundred thirty-one".
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