Base | Representation |
---|---|
bin | 11001100000101111100001… |
… | …111011000001101001000011 |
3 | 112201021022222000020120102221 |
4 | 121200233201323001221003 |
5 | 104201301100040121402 |
6 | 1034344310201351511 |
7 | 32430161565465433 |
oct | 3140574173015103 |
9 | 481238860216387 |
10 | 112201221020227 |
11 | 328292a82057a9 |
12 | 10701421a98597 |
13 | 4a7b6b6ac8a71 |
14 | 1d9c7d4b142c3 |
15 | ce8927e53337 |
hex | 660be1ec1a43 |
112201221020227 has 2 divisors, whose sum is σ = 112201221020228. Its totient is φ = 112201221020226.
The previous prime is 112201221020197. The next prime is 112201221020233. The reversal of 112201221020227 is 722020122102211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112201221020227 - 223 = 112201212631619 is a prime.
It is a super-2 number, since 2×1122012210202272 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112201221020827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56100610510113 + 56100610510114.
It is an arithmetic number, because the mean of its divisors is an integer number (56100610510114).
Almost surely, 2112201221020227 is an apocalyptic number.
112201221020227 is a deficient number, since it is larger than the sum of its proper divisors (1).
112201221020227 is an equidigital number, since it uses as much as digits as its factorization.
112201221020227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 112201221020227 its reverse (722020122102211), we get a palindrome (834221343122438).
The spelling of 112201221020227 in words is "one hundred twelve trillion, two hundred one billion, two hundred twenty-one million, twenty thousand, two hundred twenty-seven".
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