Base | Representation |
---|---|
bin | 11001100000110000011100… |
… | …111000100001100001101111 |
3 | 112201021102111221121010121212 |
4 | 121200300130320201201233 |
5 | 104201310111304021033 |
6 | 1034344552255345035 |
7 | 32430225236525261 |
oct | 3140603470414157 |
9 | 481242457533555 |
10 | 112202210220143 |
11 | 3282976562229a |
12 | 1070165922217b |
13 | 4a7b813a24164 |
14 | 1d9c88a24db31 |
15 | ce8984bee748 |
hex | 660c1ce2186f |
112202210220143 has 2 divisors, whose sum is σ = 112202210220144. Its totient is φ = 112202210220142.
The previous prime is 112202210220097. The next prime is 112202210220281. The reversal of 112202210220143 is 341022012202211.
It is a weak prime.
It is an emirp because it is prime and its reverse (341022012202211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112202210220143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112202210220043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56101105110071 + 56101105110072.
It is an arithmetic number, because the mean of its divisors is an integer number (56101105110072).
Almost surely, 2112202210220143 is an apocalyptic number.
112202210220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112202210220143 is an equidigital number, since it uses as much as digits as its factorization.
112202210220143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 112202210220143 its reverse (341022012202211), we get a palindrome (453224222422354).
The spelling of 112202210220143 in words is "one hundred twelve trillion, two hundred two billion, two hundred ten million, two hundred twenty thousand, one hundred forty-three".
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