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112202210220143 is a prime number
BaseRepresentation
bin11001100000110000011100…
…111000100001100001101111
3112201021102111221121010121212
4121200300130320201201233
5104201310111304021033
61034344552255345035
732430225236525261
oct3140603470414157
9481242457533555
10112202210220143
113282976562229a
121070165922217b
134a7b813a24164
141d9c88a24db31
15ce8984bee748
hex660c1ce2186f

112202210220143 has 2 divisors, whose sum is σ = 112202210220144. Its totient is φ = 112202210220142.

The previous prime is 112202210220097. The next prime is 112202210220281. The reversal of 112202210220143 is 341022012202211.

It is a weak prime.

It is an emirp because it is prime and its reverse (341022012202211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112202210220143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112202210220043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56101105110071 + 56101105110072.

It is an arithmetic number, because the mean of its divisors is an integer number (56101105110072).

Almost surely, 2112202210220143 is an apocalyptic number.

112202210220143 is a deficient number, since it is larger than the sum of its proper divisors (1).

112202210220143 is an equidigital number, since it uses as much as digits as its factorization.

112202210220143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 112202210220143 its reverse (341022012202211), we get a palindrome (453224222422354).

The spelling of 112202210220143 in words is "one hundred twelve trillion, two hundred two billion, two hundred ten million, two hundred twenty thousand, one hundred forty-three".