Base | Representation |
---|---|
bin | 10100111001100101… |
… | …00011111000000101 |
3 | 1001221222020010102211 |
4 | 22130302203320011 |
5 | 140434412400222 |
6 | 5053220503421 |
7 | 545024055562 |
oct | 123462437005 |
9 | 31858203384 |
10 | 11220434437 |
11 | 4838708513 |
12 | 221184ab71 |
13 | 109a7b7a24 |
14 | 786291869 |
15 | 45a0d3277 |
hex | 29cca3e05 |
11220434437 has 2 divisors, whose sum is σ = 11220434438. Its totient is φ = 11220434436.
The previous prime is 11220434359. The next prime is 11220434441. The reversal of 11220434437 is 73443402211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6815988481 + 4404445956 = 82559^2 + 66366^2 .
It is a cyclic number.
It is not a de Polignac number, because 11220434437 - 227 = 11086216709 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11220434399 and 11220434408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220434447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610217218 + 5610217219.
It is an arithmetic number, because the mean of its divisors is an integer number (5610217219).
Almost surely, 211220434437 is an apocalyptic number.
It is an amenable number.
11220434437 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220434437 is an equidigital number, since it uses as much as digits as its factorization.
11220434437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 11220434437 its reverse (73443402211), we get a palindrome (84663836648).
It can be divided in two parts, 112204 and 34437, that added together give a palindrome (146641).
The spelling of 11220434437 in words is "eleven billion, two hundred twenty million, four hundred thirty-four thousand, four hundred thirty-seven".
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