Base | Representation |
---|---|
bin | 11001100000111000110101… |
… | …011011100101111011101011 |
3 | 112201022021202022000222111222 |
4 | 121200320311123211323223 |
5 | 104201432030233013003 |
6 | 1034353041423012255 |
7 | 32430664303434323 |
oct | 3140706533457353 |
9 | 481267668028458 |
10 | 112211212001003 |
11 | 3283256491a505 |
12 | 1070334ba3a08b |
13 | 4a7c619978bcb |
14 | 1d9d0a19aa283 |
15 | ce8d1012dc38 |
hex | 660e356e5eeb |
112211212001003 has 2 divisors, whose sum is σ = 112211212001004. Its totient is φ = 112211212001002.
The previous prime is 112211212000949. The next prime is 112211212001029. The reversal of 112211212001003 is 300100212112211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112211212001003 - 210 = 112211211999979 is a prime.
It is not a weakly prime, because it can be changed into another prime (112211212021003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56105606000501 + 56105606000502.
It is an arithmetic number, because the mean of its divisors is an integer number (56105606000502).
Almost surely, 2112211212001003 is an apocalyptic number.
112211212001003 is a deficient number, since it is larger than the sum of its proper divisors (1).
112211212001003 is an equidigital number, since it uses as much as digits as its factorization.
112211212001003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 112211212001003 its reverse (300100212112211), we get a palindrome (412311424113214).
The spelling of 112211212001003 in words is "one hundred twelve trillion, two hundred eleven billion, two hundred twelve million, one thousand, three".
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