Base | Representation |
---|---|
bin | 1010001101001001111011… |
… | …1100010111000000010111 |
3 | 1110201201200020012111112002 |
4 | 2203102132330113000113 |
5 | 2432321324011401101 |
6 | 35510524550145515 |
7 | 2235461562315332 |
oct | 243223674270027 |
9 | 43651606174462 |
10 | 11221121200151 |
11 | 363693a424425 |
12 | 131288a95229b |
13 | 6351bb4b22a5 |
14 | 2ab1687d9619 |
15 | 146d4901bd6b |
hex | a349ef17017 |
11221121200151 has 2 divisors, whose sum is σ = 11221121200152. Its totient is φ = 11221121200150.
The previous prime is 11221121200123. The next prime is 11221121200231. The reversal of 11221121200151 is 15100212112211.
11221121200151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11221121200151 - 230 = 11220047458327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11221121200351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610560600075 + 5610560600076.
It is an arithmetic number, because the mean of its divisors is an integer number (5610560600076).
Almost surely, 211221121200151 is an apocalyptic number.
11221121200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11221121200151 is an equidigital number, since it uses as much as digits as its factorization.
11221121200151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 11221121200151 its reverse (15100212112211), we get a palindrome (26321333312362).
The spelling of 11221121200151 in words is "eleven trillion, two hundred twenty-one billion, one hundred twenty-one million, two hundred thousand, one hundred fifty-one".
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