Base | Representation |
---|---|
bin | 1010001101001001111011… |
… | …1100011011111000100011 |
3 | 1110201201200020020111221002 |
4 | 2203102132330123320203 |
5 | 2432321324013021011 |
6 | 35510524550422215 |
7 | 2235461562430514 |
oct | 243223674337043 |
9 | 43651606214832 |
10 | 11221121220131 |
11 | 363693a438439 |
12 | 131288a96196b |
13 | 6351bb4bb404 |
14 | 2ab168802a0b |
15 | 146d49022c3b |
hex | a349ef1be23 |
11221121220131 has 2 divisors, whose sum is σ = 11221121220132. Its totient is φ = 11221121220130.
The previous prime is 11221121220103. The next prime is 11221121220149. The reversal of 11221121220131 is 13102212112211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11221121220131 - 218 = 11221120957987 is a prime.
It is a super-2 number, since 2×112211212201312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11221121220191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610560610065 + 5610560610066.
It is an arithmetic number, because the mean of its divisors is an integer number (5610560610066).
Almost surely, 211221121220131 is an apocalyptic number.
11221121220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11221121220131 is an equidigital number, since it uses as much as digits as its factorization.
11221121220131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 11221121220131 its reverse (13102212112211), we get a palindrome (24323333332342).
The spelling of 11221121220131 in words is "eleven trillion, two hundred twenty-one billion, one hundred twenty-one million, two hundred twenty thousand, one hundred thirty-one".
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