Base | Representation |
---|---|
bin | 110100010000001011… |
… | …1010110100101110011 |
3 | 101201122020221110022222 |
4 | 1220200113112211303 |
5 | 3314302302024301 |
6 | 123314411351255 |
7 | 11051502321233 |
oct | 1504027264563 |
9 | 351566843288 |
10 | 112212142451 |
11 | 43652913512 |
12 | 198b775252b |
13 | a7738c0336 |
14 | 5606d01cc3 |
15 | 2dbb41231b |
hex | 1a205d6973 |
112212142451 has 2 divisors, whose sum is σ = 112212142452. Its totient is φ = 112212142450.
The previous prime is 112212142447. The next prime is 112212142453. The reversal of 112212142451 is 154241212211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112212142451 - 22 = 112212142447 is a prime.
Together with 112212142453, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112212142451.
It is not a weakly prime, because it can be changed into another prime (112212142453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56106071225 + 56106071226.
It is an arithmetic number, because the mean of its divisors is an integer number (56106071226).
Almost surely, 2112212142451 is an apocalyptic number.
112212142451 is a deficient number, since it is larger than the sum of its proper divisors (1).
112212142451 is an equidigital number, since it uses as much as digits as its factorization.
112212142451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1280, while the sum is 26.
Adding to 112212142451 its reverse (154241212211), we get a palindrome (266453354662).
The spelling of 112212142451 in words is "one hundred twelve billion, two hundred twelve million, one hundred forty-two thousand, four hundred fifty-one".
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