Base | Representation |
---|---|
bin | 10000010101000100001… |
… | …010101000001110110101 |
3 | 10222021102011202101110112 |
4 | 100111010022220032311 |
5 | 121341110301214143 |
6 | 2215255514232405 |
7 | 144033300324644 |
oct | 20250412501665 |
9 | 3867364671415 |
10 | 1122130101173 |
11 | 3a2990208604 |
12 | 161587125705 |
13 | 81a7c87cab3 |
14 | 3c45063335b |
15 | 1e2c872ce18 |
hex | 105442a83b5 |
1122130101173 has 2 divisors, whose sum is σ = 1122130101174. Its totient is φ = 1122130101172.
The previous prime is 1122130101091. The next prime is 1122130101193. The reversal of 1122130101173 is 3711010312211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 561993114244 + 560136986929 = 749662^2 + 748423^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122130101173 - 218 = 1122129839029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122130101193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561065050586 + 561065050587.
It is an arithmetic number, because the mean of its divisors is an integer number (561065050587).
Almost surely, 21122130101173 is an apocalyptic number.
It is an amenable number.
1122130101173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122130101173 is an equidigital number, since it uses as much as digits as its factorization.
1122130101173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 1122130101173 its reverse (3711010312211), we get a palindrome (4833140413384).
The spelling of 1122130101173 in words is "one trillion, one hundred twenty-two billion, one hundred thirty million, one hundred one thousand, one hundred seventy-three".
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