Base | Representation |
---|---|
bin | 1010001101001101001101… |
… | …0101001011000101001111 |
3 | 1110201210221111001021002101 |
4 | 2203103103111023011033 |
5 | 2432330124012321033 |
6 | 35511152104335531 |
7 | 2235522424106311 |
oct | 243232325130517 |
9 | 43653844037071 |
10 | 11222000120143 |
11 | 3637250568a8a |
12 | 1312a951745a7 |
13 | 6352cb607aa7 |
14 | 2ab20d4297b1 |
15 | 146d9b28297d |
hex | a34d354b14f |
11222000120143 has 2 divisors, whose sum is σ = 11222000120144. Its totient is φ = 11222000120142.
The previous prime is 11222000120087. The next prime is 11222000120171. The reversal of 11222000120143 is 34102100022211.
11222000120143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11222000120143 - 217 = 11221999989071 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11222000120143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11222000120843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611000060071 + 5611000060072.
It is an arithmetic number, because the mean of its divisors is an integer number (5611000060072).
Almost surely, 211222000120143 is an apocalyptic number.
11222000120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11222000120143 is an equidigital number, since it uses as much as digits as its factorization.
11222000120143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11222000120143 its reverse (34102100022211), we get a palindrome (45324100142354).
The spelling of 11222000120143 in words is "eleven trillion, two hundred twenty-two billion, one hundred twenty thousand, one hundred forty-three".
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