Base | Representation |
---|---|
bin | 1010001101010001110010… |
… | …1101110011000101001011 |
3 | 1110201221010021202022002022 |
4 | 2203110130231303011023 |
5 | 2432340134203442303 |
6 | 35511514205155055 |
7 | 2235565064056451 |
oct | 243243455630513 |
9 | 43657107668068 |
10 | 11223231312203 |
11 | 3637822539889 |
12 | 131317955ba8b |
13 | 6354667009c1 |
14 | 2ab2c8b589d1 |
15 | 146e1e3d0438 |
hex | a351cb7314b |
11223231312203 has 2 divisors, whose sum is σ = 11223231312204. Its totient is φ = 11223231312202.
The previous prime is 11223231312173. The next prime is 11223231312233. The reversal of 11223231312203 is 30221313232211.
11223231312203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (11223231312173) and next prime (11223231312233).
It is a cyclic number.
It is not a de Polignac number, because 11223231312203 - 214 = 11223231295819 is a prime.
It is not a weakly prime, because it can be changed into another prime (11223231312233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5611615656101 + 5611615656102.
It is an arithmetic number, because the mean of its divisors is an integer number (5611615656102).
Almost surely, 211223231312203 is an apocalyptic number.
11223231312203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11223231312203 is an equidigital number, since it uses as much as digits as its factorization.
11223231312203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 11223231312203 its reverse (30221313232211), we get a palindrome (41444544544414).
The spelling of 11223231312203 in words is "eleven trillion, two hundred twenty-three billion, two hundred thirty-one million, three hundred twelve thousand, two hundred three".
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