Base | Representation |
---|---|
bin | 10000010101010100100… |
… | …000101010000001101111 |
3 | 10222022010021201200211122 |
4 | 100111110200222001233 |
5 | 121342141000424101 |
6 | 2215343031411155 |
7 | 144043140141644 |
oct | 20252440520157 |
9 | 3868107650748 |
10 | 1122404311151 |
11 | 3a3010a77622 |
12 | 161642b23abb |
13 | 81ac461ac16 |
14 | 3c478c11dcb |
15 | 1e2e284551b |
hex | 1055482a06f |
1122404311151 has 2 divisors, whose sum is σ = 1122404311152. Its totient is φ = 1122404311150.
The previous prime is 1122404311121. The next prime is 1122404311159. The reversal of 1122404311151 is 1511134042211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1122404311151 - 210 = 1122404310127 is a prime.
It is a super-4 number, since 4×11224043111514 (a number of 49 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1122404311151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122404311159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561202155575 + 561202155576.
It is an arithmetic number, because the mean of its divisors is an integer number (561202155576).
Almost surely, 21122404311151 is an apocalyptic number.
1122404311151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122404311151 is an equidigital number, since it uses as much as digits as its factorization.
1122404311151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 26.
Adding to 1122404311151 its reverse (1511134042211), we get a palindrome (2633538353362).
The spelling of 1122404311151 in words is "one trillion, one hundred twenty-two billion, four hundred four million, three hundred eleven thousand, one hundred fifty-one".
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