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11224051000153 is a prime number
BaseRepresentation
bin1010001101010100110110…
…0100101010001101011001
31110202000020102010202120021
42203111031210222031121
52432343324024001103
635512131410030441
72235624306232315
oct243251544521531
943660212122507
1011224051000153
1136381031a7542
121313367b78421
13635567487c64
142ab36596ab45
15146e6b345bbd
hexa354d92a359

11224051000153 has 2 divisors, whose sum is σ = 11224051000154. Its totient is φ = 11224051000152.

The previous prime is 11224051000117. The next prime is 11224051000187. The reversal of 11224051000153 is 35100015042211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11220644176729 + 3406823424 = 3349723^2 + 58368^2 .

It is a cyclic number.

It is not a de Polignac number, because 11224051000153 - 237 = 11086612046681 is a prime.

It is not a weakly prime, because it can be changed into another prime (11224051000553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612025500076 + 5612025500077.

It is an arithmetic number, because the mean of its divisors is an integer number (5612025500077).

Almost surely, 211224051000153 is an apocalyptic number.

It is an amenable number.

11224051000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11224051000153 is an equidigital number, since it uses as much as digits as its factorization.

11224051000153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 11224051000153 its reverse (35100015042211), we get a palindrome (46324066042364).

The spelling of 11224051000153 in words is "eleven trillion, two hundred twenty-four billion, fifty-one million, one hundred fifty-three", and thus it is an aban number.