Base | Representation |
---|---|
bin | 1010001101010100110110… |
… | …0100101010001101011001 |
3 | 1110202000020102010202120021 |
4 | 2203111031210222031121 |
5 | 2432343324024001103 |
6 | 35512131410030441 |
7 | 2235624306232315 |
oct | 243251544521531 |
9 | 43660212122507 |
10 | 11224051000153 |
11 | 36381031a7542 |
12 | 1313367b78421 |
13 | 635567487c64 |
14 | 2ab36596ab45 |
15 | 146e6b345bbd |
hex | a354d92a359 |
11224051000153 has 2 divisors, whose sum is σ = 11224051000154. Its totient is φ = 11224051000152.
The previous prime is 11224051000117. The next prime is 11224051000187. The reversal of 11224051000153 is 35100015042211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11220644176729 + 3406823424 = 3349723^2 + 58368^2 .
It is a cyclic number.
It is not a de Polignac number, because 11224051000153 - 237 = 11086612046681 is a prime.
It is not a weakly prime, because it can be changed into another prime (11224051000553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612025500076 + 5612025500077.
It is an arithmetic number, because the mean of its divisors is an integer number (5612025500077).
Almost surely, 211224051000153 is an apocalyptic number.
It is an amenable number.
11224051000153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11224051000153 is an equidigital number, since it uses as much as digits as its factorization.
11224051000153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11224051000153 its reverse (35100015042211), we get a palindrome (46324066042364).
The spelling of 11224051000153 in words is "eleven trillion, two hundred twenty-four billion, fifty-one million, one hundred fifty-three", and thus it is an aban number.
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