Base | Representation |
---|---|
bin | 1010001101011001101001… |
… | …1110110100011110010001 |
3 | 1110202010120100002112201121 |
4 | 2203112122132310132101 |
5 | 2432403444334034321 |
6 | 35512503422002241 |
7 | 2236001264564134 |
oct | 243263236643621 |
9 | 43663510075647 |
10 | 11225341314961 |
11 | 363870558a114 |
12 | 1313668116381 |
13 | 6357118b1747 |
14 | 2ab44908a21b |
15 | 146ee4771441 |
hex | a359a7b4791 |
11225341314961 has 2 divisors, whose sum is σ = 11225341314962. Its totient is φ = 11225341314960.
The previous prime is 11225341314947. The next prime is 11225341315003. The reversal of 11225341314961 is 16941314352211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10225253313025 + 1000088001936 = 3197695^2 + 1000044^2 .
It is a cyclic number.
It is not a de Polignac number, because 11225341314961 - 213 = 11225341306769 is a prime.
It is not a weakly prime, because it can be changed into another prime (11225341315961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612670657480 + 5612670657481.
It is an arithmetic number, because the mean of its divisors is an integer number (5612670657481).
Almost surely, 211225341314961 is an apocalyptic number.
It is an amenable number.
11225341314961 is a deficient number, since it is larger than the sum of its proper divisors (1).
11225341314961 is an equidigital number, since it uses as much as digits as its factorization.
11225341314961 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 155520, while the sum is 43.
The spelling of 11225341314961 in words is "eleven trillion, two hundred twenty-five billion, three hundred forty-one million, three hundred fourteen thousand, nine hundred sixty-one".
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