Base | Representation |
---|---|
bin | 1010001101011001101001… |
… | …1110110100011110111011 |
3 | 1110202010120100002112210011 |
4 | 2203112122132310132323 |
5 | 2432403444334040003 |
6 | 35512503422002351 |
7 | 2236001264564224 |
oct | 243263236643673 |
9 | 43663510075704 |
10 | 11225341315003 |
11 | 363870558a152 |
12 | 13136681163b7 |
13 | 6357118b177a |
14 | 2ab44908a24b |
15 | 146ee477146d |
hex | a359a7b47bb |
11225341315003 has 2 divisors, whose sum is σ = 11225341315004. Its totient is φ = 11225341315002.
The previous prime is 11225341314961. The next prime is 11225341315007. The reversal of 11225341315003 is 30051314352211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11225341315003 - 29 = 11225341314491 is a prime.
It is not a weakly prime, because it can be changed into another prime (11225341315007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612670657501 + 5612670657502.
It is an arithmetic number, because the mean of its divisors is an integer number (5612670657502).
Almost surely, 211225341315003 is an apocalyptic number.
11225341315003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11225341315003 is an equidigital number, since it uses as much as digits as its factorization.
11225341315003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 11225341315003 its reverse (30051314352211), we get a palindrome (41276655667214).
The spelling of 11225341315003 in words is "eleven trillion, two hundred twenty-five billion, three hundred forty-one million, three hundred fifteen thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •