Base | Representation |
---|---|
bin | 11001100010001011100100… |
… | …000001001010011010111011 |
3 | 112201121210000220101210010111 |
4 | 121202023210001022122323 |
5 | 104204410440322300131 |
6 | 1034501532032325151 |
7 | 32440260455562616 |
oct | 3142134401123273 |
9 | 481553026353114 |
10 | 112300040431291 |
11 | 328671a8192969 |
12 | 107186003a37b7 |
13 | 4a87b04b4c36b |
14 | 1da34cb05917d |
15 | ceb2ad6d8ab1 |
hex | 6622e404a6bb |
112300040431291 has 2 divisors, whose sum is σ = 112300040431292. Its totient is φ = 112300040431290.
The previous prime is 112300040431289. The next prime is 112300040431333. The reversal of 112300040431291 is 192134040003211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112300040431291 - 21 = 112300040431289 is a prime.
It is a super-2 number, since 2×1123000404312912 (a number of 29 digits) contains 22 as substring.
Together with 112300040431289, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (112300040431261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56150020215645 + 56150020215646.
It is an arithmetic number, because the mean of its divisors is an integer number (56150020215646).
Almost surely, 2112300040431291 is an apocalyptic number.
112300040431291 is a deficient number, since it is larger than the sum of its proper divisors (1).
112300040431291 is an equidigital number, since it uses as much as digits as its factorization.
112300040431291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 112300040431291 in words is "one hundred twelve trillion, three hundred billion, forty million, four hundred thirty-one thousand, two hundred ninety-one".
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