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112300233313 is a prime number
BaseRepresentation
bin110100010010110011…
…1011001001001100001
3101201212101200221021111
41220211213121021201
53314442324431223
6123331235423321
711053622143012
oct1504547311141
9351771627244
10112300233313
1143698610484
1219921154b41
13a788c242c8
1456148b3009
152dc401330d
hex1a259d9261

112300233313 has 2 divisors, whose sum is σ = 112300233314. Its totient is φ = 112300233312.

The previous prime is 112300233307. The next prime is 112300233341. The reversal of 112300233313 is 313332003211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104712429649 + 7587803664 = 323593^2 + 87108^2 .

It is an emirp because it is prime and its reverse (313332003211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112300233313 - 229 = 111763362401 is a prime.

It is a super-2 number, since 2×1123002333132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112300233373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56150116656 + 56150116657.

It is an arithmetic number, because the mean of its divisors is an integer number (56150116657).

Almost surely, 2112300233313 is an apocalyptic number.

It is an amenable number.

112300233313 is a deficient number, since it is larger than the sum of its proper divisors (1).

112300233313 is an equidigital number, since it uses as much as digits as its factorization.

112300233313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 112300233313 its reverse (313332003211), we get a palindrome (425632236524).

The spelling of 112300233313 in words is "one hundred twelve billion, three hundred million, two hundred thirty-three thousand, three hundred thirteen".