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1123033147 is a prime number
BaseRepresentation
bin100001011110000…
…0010000000111011
32220021011222212021
41002330002000323
54244444030042
6303234255311
736554424055
oct10274020073
92807158767
101123033147
11526a17475
12274127537
1314b886872
14a92168d5
15688d5867
hex42f0203b

1123033147 has 2 divisors, whose sum is σ = 1123033148. Its totient is φ = 1123033146.

The previous prime is 1123033127. The next prime is 1123033231. The reversal of 1123033147 is 7413303211.

It is a weak prime.

It is an emirp because it is prime and its reverse (7413303211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1123033147 - 211 = 1123031099 is a prime.

It is a super-2 number, since 2×11230331472 = 2522406898521447218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1123033127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561516573 + 561516574.

It is an arithmetic number, because the mean of its divisors is an integer number (561516574).

Almost surely, 21123033147 is an apocalyptic number.

1123033147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123033147 is an equidigital number, since it uses as much as digits as its factorization.

1123033147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

The square root of 1123033147 is about 33511.6867226942. The cubic root of 1123033147 is about 1039.4354514265.

Adding to 1123033147 its reverse (7413303211), we get a palindrome (8536336358).

The spelling of 1123033147 in words is "one billion, one hundred twenty-three million, thirty-three thousand, one hundred forty-seven".