Base | Representation |
---|---|
bin | 10100111010110101… |
… | …11011001000010011 |
3 | 1001222201010200211221 |
4 | 22131122323020103 |
5 | 141000114443233 |
6 | 5054235345511 |
7 | 545213025154 |
oct | 123532731023 |
9 | 31881120757 |
10 | 11231015443 |
11 | 484368514a |
12 | 22152b2297 |
13 | 109ca50b8b |
14 | 78784792b |
15 | 45aec342d |
hex | 29d6bb213 |
11231015443 has 2 divisors, whose sum is σ = 11231015444. Its totient is φ = 11231015442.
The previous prime is 11231015417. The next prime is 11231015447. The reversal of 11231015443 is 34451013211.
It is a strong prime.
It is an emirp because it is prime and its reverse (34451013211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11231015443 is a prime.
It is a super-2 number, since 2×112310154432 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11231015447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615507721 + 5615507722.
It is an arithmetic number, because the mean of its divisors is an integer number (5615507722).
Almost surely, 211231015443 is an apocalyptic number.
11231015443 is a deficient number, since it is larger than the sum of its proper divisors (1).
11231015443 is an equidigital number, since it uses as much as digits as its factorization.
11231015443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11231015443 its reverse (34451013211), we get a palindrome (45682028654).
The spelling of 11231015443 in words is "eleven billion, two hundred thirty-one million, fifteen thousand, four hundred forty-three".
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