1123104450013 has 32 divisors (see below), whose sum is σ = 1455865241600. Its totient is φ = 841360291776.

The previous prime is 1123104450011. The next prime is 1123104450029. The reversal of 1123104450013 is 3100544013211.

It is a cyclic number.

It is not a de Polignac number, because 1123104450013 - 2¹ = 1123104450011 is a prime.

It is a super-2 number, since 2×1123104450013² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1123104450013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1123104450011) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2856670 + ... + 3225952.

It is an arithmetic number, because the mean of its divisors is an integer number (45495788800).

Almost surely, 2^{1123104450013} is an apocalyptic number.

1123104450013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1123104450013 is a deficient number, since it is larger than the sum of its proper divisors (332760791587).

1123104450013 is a wasteful number, since it uses less digits than its factorization.

1123104450013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371081.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1123104450013 its reverse (3100544013211), we get a palindrome (4223648463224).

The spelling of 1123104450013 in words is "one trillion, one hundred twenty-three billion, one hundred four million, four hundred fifty thousand, thirteen".