Base | Representation |
---|---|
bin | 110100010011001000… |
… | …0100101010110100000 |
3 | 101201220011000112012020 |
4 | 1220212100211112200 |
5 | 3320003110444300 |
6 | 123332303101440 |
7 | 11054113004514 |
oct | 1504620452640 |
9 | 351804015166 |
10 | 112311031200 |
11 | 436a3716055 |
12 | 199248a1880 |
13 | a78b2350a4 |
14 | 56160c4144 |
15 | 2dc4e478a0 |
hex | 1a264255a0 |
112311031200 has 288 divisors, whose sum is σ = 372621150720. Its totient is φ = 29374540800.
The previous prime is 112311031193. The next prime is 112311031241. The reversal of 112311031200 is 2130113211.
It is a happy number.
It is a super-2 number, since 2×1123110312002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 112311031200.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 102942655 + ... + 102943745.
It is an arithmetic number, because the mean of its divisors is an integer number (1293823440).
Almost surely, 2112311031200 is an apocalyptic number.
112311031200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112311031200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186310575360).
112311031200 is an abundant number, since it is smaller than the sum of its proper divisors (260310119520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112311031200 is a wasteful number, since it uses less digits than its factorization.
112311031200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1900 (or 1887 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 112311031200 its reverse (2130113211), we get a palindrome (114441144411).
The spelling of 112311031200 in words is "one hundred twelve billion, three hundred eleven million, thirty-one thousand, two hundred".
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