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112311242113212 = 22323119756725367
BaseRepresentation
bin11001100010010101111111…
…101100001100000010111100
3112201122211221120100011221200
4121202111333230030002330
5104210101410440110322
61034511023343255500
732441135164366452
oct3142257754140274
9481584846304850
10112311242113212
1132870a2625232a
121071a8078aa590
134a88b9b79c70c
141da3c70a289d2
15ceb716d158ac
hex66257fb0c0bc

112311242113212 has 18 divisors (see below), whose sum is σ = 283897862008488. Its totient is φ = 37437080704392.

The previous prime is 112311242113201. The next prime is 112311242113237. The reversal of 112311242113212 is 212311242113211.

112311242113212 is a `hidden beast` number, since 1 + 1 + 2 + 3 + 1 + 12 + 421 + 13 + 212 = 666.

It is a tau number, because it is divible by the number of its divisors (18).

It is a super-2 number, since 2×1123112421132122 (a number of 29 digits) contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1559878362648 + ... + 1559878362719.

It is an arithmetic number, because the mean of its divisors is an integer number (15772103444916).

Almost surely, 2112311242113212 is an apocalyptic number.

112311242113212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

112311242113212 is an abundant number, since it is smaller than the sum of its proper divisors (171586619895276).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112311242113212 is a wasteful number, since it uses less digits than its factorization.

112311242113212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3119756725377 (or 3119756725372 counting only the distinct ones).

The product of its digits is 1152, while the sum is 27.

Adding to 112311242113212 its reverse (212311242113211), we get a palindrome (324622484226423).

Subtracting 112311242113212 from its reverse (212311242113211), we obtain a palindrome (99999999999999).

The spelling of 112311242113212 in words is "one hundred twelve trillion, three hundred eleven billion, two hundred forty-two million, one hundred thirteen thousand, two hundred twelve".

Divisors: 1 2 3 4 6 9 12 18 36 3119756725367 6239513450734 9359270176101 12479026901468 18718540352202 28077810528303 37437080704404 56155621056606 112311242113212