Base | Representation |
---|---|
bin | 1010001101101111011111… |
… | …0000001000100100101011 |
3 | 1110202200200201022120112202 |
4 | 2203123313300020210223 |
5 | 2433002444440231443 |
6 | 35515313105330415 |
7 | 2236266430134542 |
oct | 243336760104453 |
9 | 43680621276482 |
10 | 11231201102123 |
11 | 3640142252a22 |
12 | 1314822636a0b |
13 | 6361368c7322 |
14 | 2ab8433db159 |
15 | 147238e0e7b8 |
hex | a36f7c0892b |
11231201102123 has 2 divisors, whose sum is σ = 11231201102124. Its totient is φ = 11231201102122.
The previous prime is 11231201102117. The next prime is 11231201102129. The reversal of 11231201102123 is 32120110213211.
11231201102123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (11231201102117) and next prime (11231201102129).
It is an emirp because it is prime and its reverse (32120110213211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11231201102123 - 218 = 11231200839979 is a prime.
It is a super-2 number, since 2×112312011021232 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11231201102095 and 11231201102104.
It is not a weakly prime, because it can be changed into another prime (11231201102129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615600551061 + 5615600551062.
It is an arithmetic number, because the mean of its divisors is an integer number (5615600551062).
Almost surely, 211231201102123 is an apocalyptic number.
11231201102123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11231201102123 is an equidigital number, since it uses as much as digits as its factorization.
11231201102123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11231201102123 its reverse (32120110213211), we get a palindrome (43351311315334).
The spelling of 11231201102123 in words is "eleven trillion, two hundred thirty-one billion, two hundred one million, one hundred two thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •