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11231201143 is a prime number
BaseRepresentation
bin10100111010110111…
…01000011101110111
31001222201111010120201
422131123220131313
5141000141414033
65054243341331
7545214430441
oct123533503567
931881433521
1011231201143
1148437a1718
122215381847
13109cab7566
14787895491
1545b00d47d
hex29d6e8777

11231201143 has 2 divisors, whose sum is σ = 11231201144. Its totient is φ = 11231201142.

The previous prime is 11231201099. The next prime is 11231201153. The reversal of 11231201143 is 34110213211.

It is a strong prime.

It is an emirp because it is prime and its reverse (34110213211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11231201143 is a prime.

It is a super-2 number, since 2×112312011432 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11231201143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11231201153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615600571 + 5615600572.

It is an arithmetic number, because the mean of its divisors is an integer number (5615600572).

Almost surely, 211231201143 is an apocalyptic number.

11231201143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11231201143 is an equidigital number, since it uses as much as digits as its factorization.

11231201143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11231201143 its reverse (34110213211), we get a palindrome (45341414354).

The spelling of 11231201143 in words is "eleven billion, two hundred thirty-one million, two hundred one thousand, one hundred forty-three".