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11231262557 is a prime number
BaseRepresentation
bin10100111010110111…
…10111011101011101
31001222201121020211022
422131123313131131
5141000200400212
65054244533525
7545215104464
oct123533673535
931881536738
1011231262557
114843833879
1222153b12a5
13109cb094b8
147878ad9db
1545b021772
hex29d6f775d

11231262557 has 2 divisors, whose sum is σ = 11231262558. Its totient is φ = 11231262556.

The previous prime is 11231262547. The next prime is 11231262571. The reversal of 11231262557 is 75526213211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6566509156 + 4664753401 = 81034^2 + 68299^2 .

It is an emirp because it is prime and its reverse (75526213211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11231262557 - 24 = 11231262541 is a prime.

It is a super-2 number, since 2×112312625572 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11231262547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615631278 + 5615631279.

It is an arithmetic number, because the mean of its divisors is an integer number (5615631279).

Almost surely, 211231262557 is an apocalyptic number.

It is an amenable number.

11231262557 is a deficient number, since it is larger than the sum of its proper divisors (1).

11231262557 is an equidigital number, since it uses as much as digits as its factorization.

11231262557 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25200, while the sum is 35.

Adding to 11231262557 its reverse (75526213211), we get a palindrome (86757475768).

The spelling of 11231262557 in words is "eleven billion, two hundred thirty-one million, two hundred sixty-two thousand, five hundred fifty-seven".