Base | Representation |
---|---|
bin | 110100010011001100… |
… | …0000110010101010101 |
3 | 101201220021201121122221 |
4 | 1220212120012111111 |
5 | 3320004112020201 |
6 | 123332413222341 |
7 | 11054135521324 |
oct | 1504630062525 |
9 | 351807647587 |
10 | 112313001301 |
11 | 436a4841236 |
12 | 199254919b1 |
13 | a78b774a27 |
14 | 56164780bb |
15 | 2dc51d64a1 |
hex | 1a26606555 |
112313001301 has 2 divisors, whose sum is σ = 112313001302. Its totient is φ = 112313001300.
The previous prime is 112313001221. The next prime is 112313001331. The reversal of 112313001301 is 103100313211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101969094276 + 10343907025 = 319326^2 + 101705^2 .
It is a cyclic number.
It is not a de Polignac number, because 112313001301 - 221 = 112310904149 is a prime.
It is a super-2 number, since 2×1123130013012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112313001331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56156500650 + 56156500651.
It is an arithmetic number, because the mean of its divisors is an integer number (56156500651).
Almost surely, 2112313001301 is an apocalyptic number.
It is an amenable number.
112313001301 is a deficient number, since it is larger than the sum of its proper divisors (1).
112313001301 is an equidigital number, since it uses as much as digits as its factorization.
112313001301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 112313001301 its reverse (103100313211), we get a palindrome (215413314512).
The spelling of 112313001301 in words is "one hundred twelve billion, three hundred thirteen million, one thousand, three hundred one".
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