Base | Representation |
---|---|
bin | 1010001101101111111011… |
… | …0110001010011100001011 |
3 | 1110202201000000021110200211 |
4 | 2203123332312022130023 |
5 | 2433003220422420042 |
6 | 35515333000341551 |
7 | 2236302403610605 |
oct | 243337666123413 |
9 | 43681000243624 |
10 | 11231320123147 |
11 | 36401a3456203 |
12 | 13148564748b7 |
13 | 63615546a777 |
14 | 2ab855140175 |
15 | 1472445c0017 |
hex | a36fed8a70b |
11231320123147 has 2 divisors, whose sum is σ = 11231320123148. Its totient is φ = 11231320123146.
The previous prime is 11231320123097. The next prime is 11231320123157. The reversal of 11231320123147 is 74132102313211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11231320123147 - 227 = 11231185905419 is a prime.
It is a super-2 number, since 2×112313201231472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11231320123157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615660061573 + 5615660061574.
It is an arithmetic number, because the mean of its divisors is an integer number (5615660061574).
Almost surely, 211231320123147 is an apocalyptic number.
11231320123147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11231320123147 is an equidigital number, since it uses as much as digits as its factorization.
11231320123147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 11231320123147 its reverse (74132102313211), we get a palindrome (85363422436358).
The spelling of 11231320123147 in words is "eleven trillion, two hundred thirty-one billion, three hundred twenty million, one hundred twenty-three thousand, one hundred forty-seven".
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