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112313233287007 is a prime number
BaseRepresentation
bin11001100010010111110110…
…010111111010011101011111
3112201200001002100002021220021
4121202113312113322131133
5104210120000210141012
61034511553113133011
732441235423161044
oct3142276627723537
9481601070067807
10112313233287007
1132871858210705
121071b0826ba167
134a8912817656c
141da3dbd2671cb
15ceb7d1a33007
hex6625f65fa75f

112313233287007 has 2 divisors, whose sum is σ = 112313233287008. Its totient is φ = 112313233287006.

The previous prime is 112313233286953. The next prime is 112313233287037. The reversal of 112313233287007 is 700782332313211.

It is a strong prime.

It is an emirp because it is prime and its reverse (700782332313211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112313233287007 - 215 = 112313233254239 is a prime.

It is a super-2 number, since 2×1123132332870072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112313233287037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56156616643503 + 56156616643504.

It is an arithmetic number, because the mean of its divisors is an integer number (56156616643504).

Almost surely, 2112313233287007 is an apocalyptic number.

112313233287007 is a deficient number, since it is larger than the sum of its proper divisors (1).

112313233287007 is an equidigital number, since it uses as much as digits as its factorization.

112313233287007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 254016, while the sum is 43.

The spelling of 112313233287007 in words is "one hundred twelve trillion, three hundred thirteen billion, two hundred thirty-three million, two hundred eighty-seven thousand, seven".