Base | Representation |
---|---|
bin | 11001100010010111110110… |
… | …010111111010011101011111 |
3 | 112201200001002100002021220021 |
4 | 121202113312113322131133 |
5 | 104210120000210141012 |
6 | 1034511553113133011 |
7 | 32441235423161044 |
oct | 3142276627723537 |
9 | 481601070067807 |
10 | 112313233287007 |
11 | 32871858210705 |
12 | 1071b0826ba167 |
13 | 4a8912817656c |
14 | 1da3dbd2671cb |
15 | ceb7d1a33007 |
hex | 6625f65fa75f |
112313233287007 has 2 divisors, whose sum is σ = 112313233287008. Its totient is φ = 112313233287006.
The previous prime is 112313233286953. The next prime is 112313233287037. The reversal of 112313233287007 is 700782332313211.
It is a strong prime.
It is an emirp because it is prime and its reverse (700782332313211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112313233287007 - 215 = 112313233254239 is a prime.
It is a super-2 number, since 2×1123132332870072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112313233287037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56156616643503 + 56156616643504.
It is an arithmetic number, because the mean of its divisors is an integer number (56156616643504).
Almost surely, 2112313233287007 is an apocalyptic number.
112313233287007 is a deficient number, since it is larger than the sum of its proper divisors (1).
112313233287007 is an equidigital number, since it uses as much as digits as its factorization.
112313233287007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 254016, while the sum is 43.
The spelling of 112313233287007 in words is "one hundred twelve trillion, three hundred thirteen billion, two hundred thirty-three million, two hundred eighty-seven thousand, seven".
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