Base | Representation |
---|---|
bin | 110100010011011011… |
… | …1110011000110100111 |
3 | 101201220212100210121212 |
4 | 1220212313303012213 |
5 | 3320013223424033 |
6 | 123333311302035 |
7 | 11054266251266 |
oct | 1504667630647 |
9 | 351825323555 |
10 | 112321311143 |
11 | 436a94a7578 |
12 | 1992821a91b |
13 | a7903c41b2 |
14 | 56175dc5dd |
15 | 2dc5cc8748 |
hex | 1a26df31a7 |
112321311143 has 2 divisors, whose sum is σ = 112321311144. Its totient is φ = 112321311142.
The previous prime is 112321311073. The next prime is 112321311191. The reversal of 112321311143 is 341113123211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112321311143 - 214 = 112321294759 is a prime.
It is a super-3 number, since 3×1123213111433 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112321311043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56160655571 + 56160655572.
It is an arithmetic number, because the mean of its divisors is an integer number (56160655572).
Almost surely, 2112321311143 is an apocalyptic number.
112321311143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112321311143 is an equidigital number, since it uses as much as digits as its factorization.
112321311143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 23.
Adding to 112321311143 its reverse (341113123211), we get a palindrome (453434434354).
The spelling of 112321311143 in words is "one hundred twelve billion, three hundred twenty-one million, three hundred eleven thousand, one hundred forty-three".
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