Base | Representation |
---|---|
bin | 11001100010100000001110… |
… | …001101011000000001101111 |
3 | 112201200220021212000201211201 |
4 | 121202200032031120001233 |
5 | 104210241403104043203 |
6 | 1034520041132230331 |
7 | 32442004253344201 |
oct | 3142401615300157 |
9 | 481626255021751 |
10 | 112322223112303 |
11 | 32875650792496 |
12 | 1072097130b3a7 |
13 | 4a89c2b7a3609 |
14 | 1da45d3190771 |
15 | cebb5ad9ee1d |
hex | 66280e35806f |
112322223112303 has 2 divisors, whose sum is σ = 112322223112304. Its totient is φ = 112322223112302.
The previous prime is 112322223112291. The next prime is 112322223112313. The reversal of 112322223112303 is 303211322223211.
It is a strong prime.
It is an emirp because it is prime and its reverse (303211322223211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112322223112303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112322223112313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56161111556151 + 56161111556152.
It is an arithmetic number, because the mean of its divisors is an integer number (56161111556152).
Almost surely, 2112322223112303 is an apocalyptic number.
112322223112303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112322223112303 is an equidigital number, since it uses as much as digits as its factorization.
112322223112303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 112322223112303 its reverse (303211322223211), we get a palindrome (415533545335514).
The spelling of 112322223112303 in words is "one hundred twelve trillion, three hundred twenty-two billion, two hundred twenty-three million, one hundred twelve thousand, three hundred three".
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