1123313101020 has 288 divisors, whose sum is σ = 3755075163840. Its totient is φ = 269544775680.

The previous prime is 1123313100947. The next prime is 1123313101121. The reversal of 1123313101020 is 201013133211.

1123313101020 is a `hidden beast` number, since 1 + 1 + 2 + 331 + 310 + 1 + 0 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1123313100984 and 1123313101002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 279916534 + ... + 279920546.

It is an arithmetic number, because the mean of its divisors is an integer number (13038455430).

Almost surely, 2^{1123313101020} is an apocalyptic number.

1123313101020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1123313101020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1877537581920).

1123313101020 is an abundant number, since it is smaller than the sum of its proper divisors (2631762062820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1123313101020 is a wasteful number, since it uses less digits than its factorization.

1123313101020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5445 (or 5440 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1123313101020 its reverse (201013133211), we get a palindrome (1324326234231).

The spelling of 1123313101020 in words is "one trillion, one hundred twenty-three billion, three hundred thirteen million, one hundred one thousand, twenty".