112341000011213 has 2 divisors, whose sum is σ = 112341000011214. Its totient is φ = 112341000011212.

The previous prime is 112341000011203. The next prime is 112341000011231. The reversal of 112341000011213 is 312110000143211.

Together with next prime (112341000011231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72469074817129 + 39871925194084 = 8512877^2 + 6314422^2 .

It is a cyclic number.

It is not a de Polignac number, because 112341000011213 - 2²⁸ = 112340731575757 is a prime.

It is a super-2 number, since 2×112341000011213² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112341000011203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56170500005606 + 56170500005607.

It is an arithmetic number, because the mean of its divisors is an integer number (56170500005607).

Almost surely, 2^{112341000011213} is an apocalyptic number.

It is an amenable number.

112341000011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

112341000011213 is an equidigital number, since it uses as much as digits as its factorization.

112341000011213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 112341000011213 its reverse (312110000143211), we get a palindrome (424451000154424).

The spelling of 112341000011213 in words is "one hundred twelve trillion, three hundred forty-one billion, eleven thousand, two hundred thirteen".