112341300451 has 2 divisors, whose sum is σ = 112341300452. Its totient is φ = 112341300450.

The previous prime is 112341300419. The next prime is 112341300517. The reversal of 112341300451 is 154003143211.

It is a weak prime.

It is an emirp because it is prime and its reverse (154003143211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112341300451 - 2⁵ = 112341300419 is a prime.

It is not a weakly prime, because it can be changed into another prime (112341301451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56170650225 + 56170650226.

It is an arithmetic number, because the mean of its divisors is an integer number (56170650226).

Almost surely, 2^112341300451 is an apocalyptic number.

112341300451 is a deficient number, since it is larger than the sum of its proper divisors (1).

112341300451 is an equidigital number, since it uses as much as digits as its factorization.

112341300451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 112341300451 its reverse (154003143211), we get a palindrome (266344443662).

The spelling of 112341300451 in words is "one hundred twelve billion, three hundred forty-one million, three hundred thousand, four hundred fifty-one".