Search a number
-
+
112341324300319 is a prime number
BaseRepresentation
bin11001100010110010000000…
…101110101000000000011111
3112201202201121001021121211201
4121202302000232220000133
5104211100013010102234
61034532520353100331
732443251512641042
oct3142620056500037
9481681531247751
10112341324300319
1132882762920794
12107246022576a7
134a8b983bac52a
141da54c5d48c59
15cec3c7c76314
hex662c80ba801f

112341324300319 has 2 divisors, whose sum is σ = 112341324300320. Its totient is φ = 112341324300318.

The previous prime is 112341324300229. The next prime is 112341324300323. The reversal of 112341324300319 is 913003423143211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112341324300319 - 235 = 112306964561951 is a prime.

It is a super-2 number, since 2×1123413243003192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112341324300419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56170662150159 + 56170662150160.

It is an arithmetic number, because the mean of its divisors is an integer number (56170662150160).

Almost surely, 2112341324300319 is an apocalyptic number.

112341324300319 is a deficient number, since it is larger than the sum of its proper divisors (1).

112341324300319 is an equidigital number, since it uses as much as digits as its factorization.

112341324300319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 37.

The spelling of 112341324300319 in words is "one hundred twelve trillion, three hundred forty-one billion, three hundred twenty-four million, three hundred thousand, three hundred nineteen".