Base | Representation |
---|---|
bin | 1010001101111010101010… |
… | …0001001101110101000001 |
3 | 1110202222102201212021121202 |
4 | 2203132222201031311001 |
5 | 2433030120240010103 |
6 | 35520530445030545 |
7 | 2236433646043166 |
oct | 243365241156501 |
9 | 43688381767552 |
10 | 11234200313153 |
11 | 3641441224624 |
12 | 131531ab55455 |
13 | 6364c40936cc |
14 | 2aba4987a06d |
15 | 147362399988 |
hex | a37aa84dd41 |
11234200313153 has 2 divisors, whose sum is σ = 11234200313154. Its totient is φ = 11234200313152.
The previous prime is 11234200313131. The next prime is 11234200313207. The reversal of 11234200313153 is 35131300243211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7296087070129 + 3938113243024 = 2701127^2 + 1984468^2 .
It is a cyclic number.
It is not a de Polignac number, because 11234200313153 - 28 = 11234200312897 is a prime.
It is not a weakly prime, because it can be changed into another prime (11234200318153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617100156576 + 5617100156577.
It is an arithmetic number, because the mean of its divisors is an integer number (5617100156577).
Almost surely, 211234200313153 is an apocalyptic number.
It is an amenable number.
11234200313153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234200313153 is an equidigital number, since it uses as much as digits as its factorization.
11234200313153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 11234200313153 its reverse (35131300243211), we get a palindrome (46365500556364).
The spelling of 11234200313153 in words is "eleven trillion, two hundred thirty-four billion, two hundred million, three hundred thirteen thousand, one hundred fifty-three".
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