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1123421300030 = 25671676748209
BaseRepresentation
bin10000010110010001001…
…000001010010100111110
310222101202011101002022102
4100112101020022110332
5121401231323100110
62220032001145102
7144110266331051
oct20262110122476
93871664332272
101123421300030
113a34930443a7
1216188762b192
1381c27225aa3
143c533d02a98
151e351c805a5
hex1059120a53e

1123421300030 has 16 divisors (see below), whose sum is σ = 2052339809040. Its totient is φ = 442661526912.

The previous prime is 1123421299991. The next prime is 1123421300047. The reversal of 1123421300030 is 300031243211.

It is a super-2 number, since 2×11234213000302 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123421299975 and 1123421300011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 838373435 + ... + 838374774.

It is an arithmetic number, because the mean of its divisors is an integer number (128271238065).

Almost surely, 21123421300030 is an apocalyptic number.

1123421300030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1123421300030 is a deficient number, since it is larger than the sum of its proper divisors (928918509010).

1123421300030 is a wasteful number, since it uses less digits than its factorization.

1123421300030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1676748283.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1123421300030 its reverse (300031243211), we get a palindrome (1423452543241).

The spelling of 1123421300030 in words is "one trillion, one hundred twenty-three billion, four hundred twenty-one million, three hundred thousand, thirty".

Divisors: 1 2 5 10 67 134 335 670 1676748209 3353496418 8383741045 16767482090 112342130003 224684260006 561710650015 1123421300030