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1123434330121 is a prime number
BaseRepresentation
bin10000010110010001111…
…001110111100000001001
310222101210001220002020101
4100112101321313200021
5121401243142030441
62220033144325401
7144110515150465
oct20262171674011
93871701802211
101123434330121
113a349a434074
1216188ba73861
1381c29b388bc
143c5359354a5
151e352ea6231
hex10591e77809

1123434330121 has 2 divisors, whose sum is σ = 1123434330122. Its totient is φ = 1123434330120.

The previous prime is 1123434330119. The next prime is 1123434330143. The reversal of 1123434330121 is 1210334343211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 576331497225 + 547102832896 = 759165^2 + 739664^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123434330121 - 21 = 1123434330119 is a prime.

Together with 1123434330119, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1123434330121.

It is not a weakly prime, because it can be changed into another prime (1123434330181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561717165060 + 561717165061.

It is an arithmetic number, because the mean of its divisors is an integer number (561717165061).

Almost surely, 21123434330121 is an apocalyptic number.

It is an amenable number.

1123434330121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123434330121 is an equidigital number, since it uses as much as digits as its factorization.

1123434330121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1123434330121 its reverse (1210334343211), we get a palindrome (2333768673332).

The spelling of 1123434330121 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, three hundred thirty thousand, one hundred twenty-one".