1123434411137 has 2 divisors, whose sum is σ = 1123434411138. Its totient is φ = 1123434411136.

The previous prime is 1123434411107. The next prime is 1123434411163. The reversal of 1123434411137 is 7311144343211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 965186388721 + 158248022416 = 982439^2 + 397804^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123434411137 - 2¹⁰ = 1123434410113 is a prime.

It is a super-2 number, since 2×1123434411137² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123434411097 and 1123434411106.

It is not a weakly prime, because it can be changed into another prime (1123434411107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561717205568 + 561717205569.

It is an arithmetic number, because the mean of its divisors is an integer number (561717205569).

Almost surely, 2^{1123434411137} is an apocalyptic number.

It is an amenable number.

1123434411137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123434411137 is an equidigital number, since it uses as much as digits as its factorization.

1123434411137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24192, while the sum is 35.

Adding to 1123434411137 its reverse (7311144343211), we get a palindrome (8434578754348).

The spelling of 1123434411137 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, four hundred eleven thousand, one hundred thirty-seven".