Base | Representation |
---|---|
bin | 10000010110010010000… |
… | …001100010111101101111 |
3 | 10222101210012200100121001 |
4 | 100112102001202331233 |
5 | 121401244200440101 |
6 | 2220033255421131 |
7 | 144110541233413 |
oct | 20262201427557 |
9 | 3871705610531 |
10 | 1123436343151 |
11 | 3a34a0589531 |
12 | 1618906847a7 |
13 | 81c2a391c45 |
14 | 3c535cdad43 |
15 | 1e353252901 |
hex | 10592062f6f |
1123436343151 has 2 divisors, whose sum is σ = 1123436343152. Its totient is φ = 1123436343150.
The previous prime is 1123436343137. The next prime is 1123436343313. The reversal of 1123436343151 is 1513436343211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1123436343151 - 229 = 1122899472239 is a prime.
It is a super-2 number, since 2×11234363431512 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1123436343151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123436343751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561718171575 + 561718171576.
It is an arithmetic number, because the mean of its divisors is an integer number (561718171576).
Almost surely, 21123436343151 is an apocalyptic number.
1123436343151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123436343151 is an equidigital number, since it uses as much as digits as its factorization.
1123436343151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 37.
The spelling of 1123436343151 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-six million, three hundred forty-three thousand, one hundred fifty-one".
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