Base | Representation |
---|---|
bin | 110100010100000110… |
… | …1001110111000111001 |
3 | 101201222102111122020012 |
4 | 1220220031032320321 |
5 | 3320034442112233 |
6 | 123335431311305 |
7 | 11054660520014 |
oct | 1505015167071 |
9 | 351872448205 |
10 | 112343707193 |
11 | 43710104003 |
12 | 1993381b535 |
13 | a794c360b3 |
14 | 561a58c37b |
15 | 2dc7c4e548 |
hex | 1a2834ee39 |
112343707193 has 2 divisors, whose sum is σ = 112343707194. Its totient is φ = 112343707192.
The previous prime is 112343707169. The next prime is 112343707219. The reversal of 112343707193 is 391707343211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92035177129 + 20308530064 = 303373^2 + 142508^2 .
It is a cyclic number.
It is not a de Polignac number, because 112343707193 - 222 = 112339512889 is a prime.
It is a super-2 number, since 2×1123437071932 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 112343707193.
It is not a weakly prime, because it can be changed into another prime (112343707393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56171853596 + 56171853597.
It is an arithmetic number, because the mean of its divisors is an integer number (56171853597).
Almost surely, 2112343707193 is an apocalyptic number.
It is an amenable number.
112343707193 is a deficient number, since it is larger than the sum of its proper divisors (1).
112343707193 is an equidigital number, since it uses as much as digits as its factorization.
112343707193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 95256, while the sum is 41.
The spelling of 112343707193 in words is "one hundred twelve billion, three hundred forty-three million, seven hundred seven thousand, one hundred ninety-three".
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