1123444410433 has 2 divisors, whose sum is σ = 1123444410434. Its totient is φ = 1123444410432.

The previous prime is 1123444410337. The next prime is 1123444410449. The reversal of 1123444410433 is 3340144443211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 785125361329 + 338319049104 = 886073^2 + 581652^2 .

It is an emirp because it is prime and its reverse (3340144443211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1123444410433 - 2²⁹ = 1122907539521 is a prime.

It is not a weakly prime, because it can be changed into another prime (1123444410233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561722205216 + 561722205217.

It is an arithmetic number, because the mean of its divisors is an integer number (561722205217).

Almost surely, 2^{1123444410433} is an apocalyptic number.

It is an amenable number.

1123444410433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123444410433 is an equidigital number, since it uses as much as digits as its factorization.

1123444410433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 1123444410433 its reverse (3340144443211), we get a palindrome (4463588853644).

The spelling of 1123444410433 in words is "one trillion, one hundred twenty-three billion, four hundred forty-four million, four hundred ten thousand, four hundred thirty-three".