Base | Representation |
---|---|
bin | 1101011001000… |
… | …11111100111101 |
3 | 21211101201012222 |
4 | 12230203330331 |
5 | 212230014033 |
6 | 15051535125 |
7 | 2532626063 |
oct | 654437475 |
9 | 254351188 |
10 | 112344893 |
11 | 58463421 |
12 | 3175a4a5 |
13 | 1a37678b |
14 | 10cc6033 |
15 | 9ce2598 |
hex | 6b23f3d |
112344893 has 2 divisors, whose sum is σ = 112344894. Its totient is φ = 112344892.
The previous prime is 112344887. The next prime is 112344901. The reversal of 112344893 is 398443211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83850649 + 28494244 = 9157^2 + 5338^2 .
It is an emirp because it is prime and its reverse (398443211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112344893 - 216 = 112279357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112344803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56172446 + 56172447.
It is an arithmetic number, because the mean of its divisors is an integer number (56172447).
Almost surely, 2112344893 is an apocalyptic number.
It is an amenable number.
112344893 is a deficient number, since it is larger than the sum of its proper divisors (1).
112344893 is an equidigital number, since it uses as much as digits as its factorization.
112344893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 35.
The square root of 112344893 is about 10599.2873817064. The cubic root of 112344893 is about 482.5227322462.
The spelling of 112344893 in words is "one hundred twelve million, three hundred forty-four thousand, eight hundred ninety-three".
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