Base | Representation |
---|---|
bin | 10000010110010100110… |
… | …001100101011001001111 |
3 | 10222101220102111212210011 |
4 | 100112110301211121033 |
5 | 121401343004143242 |
6 | 2220042024454051 |
7 | 144111641413552 |
oct | 20262461453117 |
9 | 3871812455704 |
10 | 1123482490447 |
11 | 3a3514638699 |
12 | 1618a401a327 |
13 | 81c36acb835 |
14 | 3c53c0b0699 |
15 | 1e35731ad17 |
hex | 10594c6564f |
1123482490447 has 2 divisors, whose sum is σ = 1123482490448. Its totient is φ = 1123482490446.
The previous prime is 1123482490439. The next prime is 1123482490453. The reversal of 1123482490447 is 7440942843211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123482490447 - 23 = 1123482490439 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1123482490447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123482494447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561741245223 + 561741245224.
It is an arithmetic number, because the mean of its divisors is an integer number (561741245224).
Almost surely, 21123482490447 is an apocalyptic number.
1123482490447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123482490447 is an equidigital number, since it uses as much as digits as its factorization.
1123482490447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1548288, while the sum is 49.
The spelling of 1123482490447 in words is "one trillion, one hundred twenty-three billion, four hundred eighty-two million, four hundred ninety thousand, four hundred forty-seven".
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