Base | Representation |
---|---|
bin | 10100111011110110… |
… | …01111110011101111 |
3 | 1002000022002012001011 |
4 | 22131323033303233 |
5 | 141004302120001 |
6 | 5055141130051 |
7 | 545345035531 |
oct | 123573176357 |
9 | 32008065034 |
10 | 11239488751 |
11 | 4848442287 |
12 | 22180b9927 |
13 | 10a172987a |
14 | 788a11851 |
15 | 45bae8d51 |
hex | 29decfcef |
11239488751 has 2 divisors, whose sum is σ = 11239488752. Its totient is φ = 11239488750.
The previous prime is 11239488719. The next prime is 11239488829. The reversal of 11239488751 is 15788493211.
It is a weak prime.
It is an emirp because it is prime and its reverse (15788493211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11239488751 - 25 = 11239488719 is a prime.
It is a super-2 number, since 2×112394887512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11239488695 and 11239488704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11239488151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5619744375 + 5619744376.
It is an arithmetic number, because the mean of its divisors is an integer number (5619744376).
Almost surely, 211239488751 is an apocalyptic number.
11239488751 is a deficient number, since it is larger than the sum of its proper divisors (1).
11239488751 is an equidigital number, since it uses as much as digits as its factorization.
11239488751 is an evil number, because the sum of its binary digits is even.
The product of its digits is 483840, while the sum is 49.
The spelling of 11239488751 in words is "eleven billion, two hundred thirty-nine million, four hundred eighty-eight thousand, seven hundred fifty-one".
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