Base | Representation |
---|---|
bin | 110100010101110010… |
… | …1100011011001011111 |
3 | 101202010101012122202112 |
4 | 1220223211203121133 |
5 | 3320144001224203 |
6 | 123345214544235 |
7 | 11056246520612 |
oct | 1505345433137 |
9 | 352111178675 |
10 | 112400414303 |
11 | 4373a115991 |
12 | 1994a80807b |
13 | a7a38cc2b8 |
14 | 5623d10179 |
15 | 2dccc016d8 |
hex | 1a2b96365f |
112400414303 has 2 divisors, whose sum is σ = 112400414304. Its totient is φ = 112400414302.
The previous prime is 112400414299. The next prime is 112400414333. The reversal of 112400414303 is 303414004211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112400414303 - 22 = 112400414299 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112400414333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56200207151 + 56200207152.
It is an arithmetic number, because the mean of its divisors is an integer number (56200207152).
Almost surely, 2112400414303 is an apocalyptic number.
112400414303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112400414303 is an equidigital number, since it uses as much as digits as its factorization.
112400414303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 112400414303 its reverse (303414004211), we get a palindrome (415814418514).
The spelling of 112400414303 in words is "one hundred twelve billion, four hundred million, four hundred fourteen thousand, three hundred three".
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