Base | Representation |
---|---|
bin | 10100111100000010… |
… | …01010111000100011 |
3 | 1002000102000001221021 |
4 | 22132001022320203 |
5 | 141010201311233 |
6 | 5055234310311 |
7 | 545364163402 |
oct | 123601127043 |
9 | 32012001837 |
10 | 11241041443 |
11 | 48493028a5 |
12 | 2218728397 |
13 | 10a1b51518 |
14 | 788cd7639 |
15 | 45bd03e2d |
hex | 29e04ae23 |
11241041443 has 2 divisors, whose sum is σ = 11241041444. Its totient is φ = 11241041442.
The previous prime is 11241041407. The next prime is 11241041453. The reversal of 11241041443 is 34414014211.
It is a strong prime.
It is an emirp because it is prime and its reverse (34414014211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11241041443 - 233 = 2651106851 is a prime.
It is a super-2 number, since 2×112410414432 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11241041453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620520721 + 5620520722.
It is an arithmetic number, because the mean of its divisors is an integer number (5620520722).
Almost surely, 211241041443 is an apocalyptic number.
11241041443 is a deficient number, since it is larger than the sum of its proper divisors (1).
11241041443 is an equidigital number, since it uses as much as digits as its factorization.
11241041443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11241041443 its reverse (34414014211), we get a palindrome (45655055654).
The spelling of 11241041443 in words is "eleven billion, two hundred forty-one million, forty-one thousand, four hundred forty-three".
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