11241114433 has 2 divisors, whose sum is σ = 11241114434. Its totient is φ = 11241114432.

The previous prime is 11241114427. The next prime is 11241114523. The reversal of 11241114433 is 33441114211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8094241024 + 3146873409 = 89968^2 + 56097^2 .

It is a cyclic number.

It is not a de Polignac number, because 11241114433 - 2²¹ = 11239017281 is a prime.

It is a super-2 number, since 2×11241114433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11241114398 and 11241114407.

It is not a weakly prime, because it can be changed into another prime (11241114413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620557216 + 5620557217.

It is an arithmetic number, because the mean of its divisors is an integer number (5620557217).

Almost surely, 2^11241114433 is an apocalyptic number.

It is an amenable number.

11241114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11241114433 is an equidigital number, since it uses as much as digits as its factorization.

11241114433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 11241114433 its reverse (33441114211), we get a palindrome (44682228644).

The spelling of 11241114433 in words is "eleven billion, two hundred forty-one million, one hundred fourteen thousand, four hundred thirty-three".